Right mandrel/mold for 90° bent carbon fiber tubes


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zeiss
zeiss
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Hi all,
i'm buying some carbon fiber sleeves like the one in the image..
roughly 20 cm right + a 90° curve + another 20 cm right
with the diameter of 21 mm.

Upon your opinion what's the best and simple mandrel to create..

A copper tube rounded with pipe insulation foam...?
I read in some article that it could be the right solution..
I think only that it should not be so easy to take out 
the copper tube once the carbon fiber is cured..

I imagine a different solution, the opposite of the previous one.
I would like to try to use  a rubber hose of roughly 45 cm 
( those used to water the garden). I do not know the technical term (I'm not native English speakers ..)

The outer diameter of the pipe must be equal to that which you want to obtain less the thickness of the sleeve of carbon fibers.

Then I would insert each of the two ends of the rubber tube two pieces of an adequate diametered rigid tube (aluminum stainless steel ...) 
for a length of about 15 centimeters into the rubber hose...
 Then I subdue the rubber tube by holding the ends of the two metal tubes and would insert it into a kind of template that keep it fixed and positioned so as to create the shape I wish.  I_

once the carbon fiber is cured... i think that it could be more easy to take off the carbon fiber tube the mandrel..
First i could take off the metal pipe from the rubber hose..it should be easier than the first idea..
Tha pipe are straight... Then taking off the rubber hose from the carbon fiber tube created it should be not so difficult 
because rubber i think it's more easy to go in the curves than copper.... :-)  

What do you think about my idea...?
It might work ..? This will be my first attempt in the world of composites ..

Do you have any different ideas or suggestions..?

Thank you very much for taking the time in answering.
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Curved tubes.jpg (3K views, 98.00 KB)
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zeiss
zeiss
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Ok..
Thank you Warren for your reply..It's clear..

1) It's a little more difficult to work with the 20mm to adapt to a 21mm mandrel 
    but i'll obtain the maxx strenght as the fiber are more close to te rest position at 45°..

2) it's more easy to work with the 40mm and stretching to 21mm...but the final product has a littel less strenght..
    as the fiber as less close to 45° ...



Just a question about the lenght of a braided sleeve..

In the hypothesis that :

1) the surface area of the sleeve remain roughly costant through the extension limits pushing or pulling the sleeve..

2) the lenghts you are selling are taken when the sleeve is in rest position (fibers at 45° no pull no push..)

i think  it should be correct to write that : 

Lx = Dres / Dx * Lres

Where :

Lx     -> is the lenght of the sleeve at the diameter Dx i'd like to make
Dx    ->  is the diameter of the tubes i'd like to make.
Dres ->  Is the diameter of the Sleeve at rest (without any force applied)
Lres  -> Is the lenght of the sleeve at rest (without any force applied)

So for example if i'll buy 1 meter of Lightweight Braided Carbon Fibre Sleeve 40mm

i'll have a sleeve of roughly  :

Lx = 40 / 21 * 1000 = 1904 mm

On the other hand, if i'll buy 1 meter of  Lightweight Braided Carbon Fibre Sleeve 20mm

I'll have a sleeve of roughly :

Lx = 20 /21 * 1000 = 952 mm

Waiting for you reply..
Thank you very much....

Zeiss.
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