Front splitter force estimation.

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Front splitter force estimation.

Front splitter force estimation.

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Para	P Para posted 5 Years Ago HOT Topic Details
P Group: Forum Members Posts: 8, Visits: 20	Dear Sir/Madam, Is there an empirical data available on what the loads (lbs or Newton) are on a typical splitter for an average passenger car at various speeds?....or is there an easy way to calculate/estimate the force for a given splitter size/area ? Thanks in advance kindest regards
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Warren (Staff)	Warren (Staff) posted 5 Years Ago HOT Post Details
Group: Administrators Posts: 2.5K, Visits: 8.5K	I am not aware of any off the shelf data. Do you mean aerodynamic loadings or strength of a typical splitter? both could be quite different and are effected by different variables although one would hope any decent splitter is strong enough to resist the aerodynamic loads it is designed to take! Warren Penalver Easy Composites / Carbon Mods - Technical Support Assistant
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Front splitter force estimation.

Para - 5 Years Ago

I am not aware of any off the shelf data. Do you mean aerodynamic loadings or strength of a typical splitter? both could be quite different and are effected by different variables although one would....

Warren (Staff) - 5 Years Ago

Totally impossible to give a generic value for. The same splitter on one car will perform differently on another car, let alone different splitters. Variables like rake angle, leading edge thickness,...

Hanaldo - 5 Years Ago

Hi Guys, First of all, thank you to everyone for getting back back....much appreciated. I realise that the splitter itself does not actually create downforce (unlike an airfoil). All it does is to.....

Para - 5 Years Ago

Splitters do create downforce, just not as much as an airfoil. The main function of a splitter is to reduce the amount of air going underneath the car. As with all aero structures, the high pressure....

Hanaldo - 5 Years Ago

+ x [quote] [b] Hanaldo - 3/4/2020 2:42:57 AM [/b] + x [quote] [b]...

Para - 5 Years Ago

Hi Hanaldo, Thanks for that. Indeed those are huge loads. However if you look at data from passenger cars modified into track cars, you will see that no such vehicle capable of generating more than....

Para - 5 Years Ago

I'm not talking about Radicals or the likes, I'm talking about Time Attack cars. Take a look at any of the Pro or Pro Am cars competing at WTAC. These cars are all making more downforce than an F1...

Hanaldo - 5 Years Ago

So what sort of lateral acceleration can these Time Attack cars muster? I couldn’t find any data on that, but I suspect no where near an F1 car…or even a Radical ….i guess one of the limiting factors...

Para - 5 Years Ago

Yeh you won't find that sort of data published, the teams will keep that information pretty close. I know the race engineer for the Tilton Evo, I'll see if I can get it out of him. However these car...

Hanaldo - 5 Years Ago

You won't find any data on the time attack cars as most of them are privately built. The top cars hire an aero engineer to design and cfd/wind tunnel test, which usually done so under a hefty NDA....

leeks - 5 Years Ago

Regarding the time posted, I’m not familiar with the Australian circuit....but obviously mind blowingly quick when referenced to an SR8....although I’m just curious if the Time Attack cars are still...

Para - 5 Years Ago

They wont be anywhere near an F1 cars lateral acceleration, but they will be surpassing an SR8 Radical by quite a bit assuming Googles data on the SR8 is correct. A quick search tells me an SR8 is....

Hanaldo - 5 Years Ago

OK no problem....perhaps Tilton do not wish to disclose such data...which is understandable.....so Pro Am cars, around 4-5 Gs is F1 territory

Para - 5 Years Ago

I believe modern F1 cars are up around 8 lat G's through the high speed corners. But that said, I cant think of many corners in the F1 schedule that are taken at over 300km/h, which the top Time...

Hanaldo - 5 Years Ago

Indeed.... 300 kph = 83.3 m/s So 8 g cornering at 300 kph would require a corner radius (constant) of: r = v^2/(G.g) = 83.3^2/(8 x 9.81) = 88.4 m. There may be a few circuits meeting this requirement...

Para - 5 Years Ago

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